1/3(6x+3)=1/6(12x+6)

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Solution for 1/3(6x+3)=1/6(12x+6) equation: 



1/3(6x+3)=1/6(12x+6)

We move all terms to the left:

1/3(6x+3)-(1/6(12x+6))=0



Domain of the equation: 3(6x+3)!=0

x∈R





Domain of the equation: 6(12x+6))!=0

x∈R



We calculate fractions


(6x1/(3(6x+3)*6(12x+6)))+(-3x6/(3(6x+3)*6(12x+6)))=0



We calculate terms in parentheses: +(6x1/(3(6x+3)*6(12x+6))), so:

6x1/(3(6x+3)*6(12x+6))

We multiply all the terms by the denominator


6x1

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-3x6/(3(6x+3)*6(12x+6))), so:

-3x6/(3(6x+3)*6(12x+6))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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