(X4-x2-3)2=(2x2+4)3

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Solution for (X4-x2-3)2=(2x2+4)3 equation: 



(X4-X2-3)2=(2X^2+4)3

We move all terms to the left:

(X4-X2-3)2-((2X^2+4)3)=0

We add all the numbers together, and all the variables

(+X^4-1X^2-3)2-((2X^2+4)3)=0

We multiply parentheses

2X^4-2X^2-((2X^2+4)3)-6=0



We calculate terms in parentheses: -((2X^2+4)3), so:

(2X^2+4)3

We multiply parentheses

6X^2+12

Back to the equation:

-(6X^2+12)



We do not support eXpression: X^4

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