5x+32-7x=40-(x+2)

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Solution for 5x+32-7x=40-(x+2) equation: 



5x+32-7x=40-(x+2)

We move all terms to the left:

5x+32-7x-(40-(x+2))=0

We add all the numbers together, and all the variables

-2x-(40-(x+2))+32=0



We calculate terms in parentheses: -(40-(x+2)), so:

40-(x+2)

determiningTheFunctionDomain
-(x+2)+40

We get rid of parentheses

-x-2+40

We add all the numbers together, and all the variables

-1x+38

Back to the equation:

-(-1x+38)



We get rid of parentheses

-2x+1x-38+32=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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