1/3(6t+12)=-3(2t-4

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Solution for 1/3(6t+12)=-3(2t-4 equation:



1/3(6t+12)=-3(2t-4
We move all terms to the left:
1/3(6t+12)-(-3(2t-4)=0
Domain of the equation: 3(6t+12)!=0
t∈R
We multiply all the terms by the denominator
-((-3(2t-4))*3(6t+12)+1=0

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