B-24=3(b-6)-4

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Solution for B-24=3(b-6)-4 equation: 



-24=3(B-6)-4

We move all terms to the left:

-24-(3(B-6)-4)=0



We calculate terms in parentheses: -(3(B-6)-4), so:

3(B-6)-4

We multiply parentheses

3B-18-4

We add all the numbers together, and all the variables

3B-22

Back to the equation:

-(3B-22)



We get rid of parentheses

-3B+22-24=0

We add all the numbers together, and all the variables

-3B-2=0

We move all terms containing B to the left, all other terms to the right

-3B=2

B=2/-3

B=-2/3

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