1/3(6h-12)=-5h+17

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Solution for 1/3(6h-12)=-5h+17 equation: 



1/3(6h-12)=-5h+17

We move all terms to the left:

1/3(6h-12)-(-5h+17)=0



Domain of the equation: 3(6h-12)!=0

h∈R



We get rid of parentheses

1/3(6h-12)+5h-17=0

We multiply all the terms by the denominator


5h*3(6h-12)-17*3(6h-12)+1=0

Wy multiply elements

15h^2(6-51h(6+1=0

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