1/4(u+3)=9/4-u

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Solution for 1/4(u+3)=9/4-u equation: 



1/4(u+3)=9/4-u

We move all terms to the left:

1/4(u+3)-(9/4-u)=0



Domain of the equation: 4(u+3)!=0

u∈R





Domain of the equation: 4-u)!=0

We move all terms containing u to the left, all other terms to the right

-u)!=-4

u!=-4/1

u!=-4

u∈R



We add all the numbers together, and all the variables

1/4(u+3)-(-1u+9/4)=0

We get rid of parentheses

1/4(u+3)+1u-9/4=0

We calculate fractions


u=0

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