1/3(6-9y)=1/4(8y+48)

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Solution for 1/3(6-9y)=1/4(8y+48) equation: 



1/3(6-9y)=1/4(8y+48)

We move all terms to the left:

1/3(6-9y)-(1/4(8y+48))=0



Domain of the equation: 3(6-9y)!=0

y∈R





Domain of the equation: 4(8y+48))!=0

y∈R



We add all the numbers together, and all the variables

1/3(-9y+6)-(1/4(8y+48))=0

We calculate fractions


(4y8/(3(-9y+6)*4(8y+48)))+(-3y0/(3(-9y+6)*4(8y+48)))=0



We calculate terms in parentheses: +(4y8/(3(-9y+6)*4(8y+48))), so:

4y8/(3(-9y+6)*4(8y+48))

We multiply all the terms by the denominator


4y8

We add all the numbers together, and all the variables

4y^8

We do not support eypression: y^8

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