6(5k+1)=2(3k-2)

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Solution for 6(5k+1)=2(3k-2) equation: 



6(5k+1)=2(3k-2)

We move all terms to the left:

6(5k+1)-(2(3k-2))=0

We multiply parentheses

30k-(2(3k-2))+6=0



We calculate terms in parentheses: -(2(3k-2)), so:

2(3k-2)

We multiply parentheses

6k-4

Back to the equation:

-(6k-4)



We get rid of parentheses

30k-6k+4+6=0

We add all the numbers together, and all the variables

24k+10=0

We move all terms containing k to the left, all other terms to the right

24k=-10

k=-10/24

k=-5/12

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