1/3(3y-6)=1/2(2y-6)

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Solution for 1/3(3y-6)=1/2(2y-6) equation: 



1/3(3y-6)=1/2(2y-6)

We move all terms to the left:

1/3(3y-6)-(1/2(2y-6))=0



Domain of the equation: 3(3y-6)!=0

y∈R





Domain of the equation: 2(2y-6))!=0

y∈R



We calculate fractions


(2y2/(3(3y-6)*2(2y-6)))+(-3y3/(3(3y-6)*2(2y-6)))=0



We calculate terms in parentheses: +(2y2/(3(3y-6)*2(2y-6))), so:

2y2/(3(3y-6)*2(2y-6))

We multiply all the terms by the denominator


2y2

We add all the numbers together, and all the variables

2y^2

Back to the equation:

+(2y^2)





We calculate terms in parentheses: +(-3y3/(3(3y-6)*2(2y-6))), so:

-3y3/(3(3y-6)*2(2y-6))

We multiply all the terms by the denominator


-3y3

We add all the numbers together, and all the variables

-3y^3

We do not support eypression: y^3

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