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x-3/10x=100
We move all terms to the left:
x-3/10x-(100)=0
Domain of the equation: 10x!=0We multiply all the terms by the denominator
x!=0/10
x!=0
x∈R
x*10x-100*10x-3=0
Wy multiply elements
10x^2-1000x-3=0
a = 10; b = -1000; c = -3;
Δ = b2-4ac
Δ = -10002-4·10·(-3)
Δ = 1000120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1000120}=\sqrt{4*250030}=\sqrt{4}*\sqrt{250030}=2\sqrt{250030}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1000)-2\sqrt{250030}}{2*10}=\frac{1000-2\sqrt{250030}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1000)+2\sqrt{250030}}{2*10}=\frac{1000+2\sqrt{250030}}{20} $
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