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1/3(3x-6)=12-x
We move all terms to the left:
1/3(3x-6)-(12-x)=0
Domain of the equation: 3(3x-6)!=0We add all the numbers together, and all the variables
x∈R
1/3(3x-6)-(-1x+12)=0
We get rid of parentheses
1/3(3x-6)+1x-12=0
We multiply all the terms by the denominator
1x*3(3x-6)-12*3(3x-6)+1=0
Wy multiply elements
3x^2(3-36x(3+1=0
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