-4(3-3p)+12=4(p-2)

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Solution for -4(3-3p)+12=4(p-2) equation: 



-4(3-3p)+12=4(p-2)

We move all terms to the left:

-4(3-3p)+12-(4(p-2))=0

We add all the numbers together, and all the variables

-4(-3p+3)-(4(p-2))+12=0

We multiply parentheses

12p-(4(p-2))-12+12=0



We calculate terms in parentheses: -(4(p-2)), so:

4(p-2)

We multiply parentheses

4p-8

Back to the equation:

-(4p-8)



We add all the numbers together, and all the variables

12p-(4p-8)=0

We get rid of parentheses

12p-4p+8=0

We add all the numbers together, and all the variables

8p+8=0

We move all terms containing p to the left, all other terms to the right

8p=-8

p=-8/8

p=-1

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