1/3(3a-1)+2/5(4a+3)=3/5(a-7)+1=a

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Solution for 1/3(3a-1)+2/5(4a+3)=3/5(a-7)+1=a equation: 



1/3(3a-1)+2/5(4a+3)=3/5(a-7)+1=a

We move all terms to the left:

1/3(3a-1)+2/5(4a+3)-(3/5(a-7)+1)=0



Domain of the equation: 3(3a-1)!=0

a∈R





Domain of the equation: 5(4a+3)!=0

a∈R





Domain of the equation: 5(a-7)+1)!=0

a∈R



We calculate fractions

We do not support eapression: a^23

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