(8-v)(3v+4)=0

Solution for (8-v)(3v+4)=0 equation:

(8-v)(3v+4)=0

We add all the numbers together, and all the variables

(-1v+8)(3v+4)=0

We multiply parentheses ..

(-3v^2-4v+24v+32)=0

We get rid of parentheses

-3v^2-4v+24v+32=0

We add all the numbers together, and all the variables

-3v^2+20v+32=0

a = -3; b = 20; c = +32;
Δ = b2-4ac
Δ = 202-4·(-3)·32
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*-3}=\frac{-48}{-6}
=+8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*-3}=\frac{8}{-6}
=-1+1/3
$