1/3(2y+1)+1/2y=2/5(1-2y)-4

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Solution for 1/3(2y+1)+1/2y=2/5(1-2y)-4 equation: 



1/3(2y+1)+1/2y=2/5(1-2y)-4

We move all terms to the left:

1/3(2y+1)+1/2y-(2/5(1-2y)-4)=0



Domain of the equation: 3(2y+1)!=0

y∈R





Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R





Domain of the equation: 5(1-2y)-4)!=0

y∈R



We add all the numbers together, and all the variables

1/3(2y+1)+1/2y-(2/5(-2y+1)-4)=0

We calculate fractions


50y^2/(3(2y+1)*2y*5(-2y+1))+(15y^22/(3(2y+1)*2y*5(-2y+1))+(-(2*3(2y+1)*2y)/(3(2y+1)*2y*5(-2y+1))=0



We calculate terms in parentheses: +(15y^22/(3(2y+1)*2y*5(-2y+1))+(-(2*3(2y+1)*2y)/(3(2y+1)*2y*5(-2y+1)), so:

15y^22/(3(2y+1)*2y*5(-2y+1))+(-(2*3(2y+1)*2y)/(3(2y+1)*2y*5(-2y+1)

We do not support eypression: y^22

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