4x-(2x-8)=8(x-5)+12

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Solution for 4x-(2x-8)=8(x-5)+12 equation: 



4x-(2x-8)=8(x-5)+12

We move all terms to the left:

4x-(2x-8)-(8(x-5)+12)=0

We get rid of parentheses

4x-2x-(8(x-5)+12)+8=0



We calculate terms in parentheses: -(8(x-5)+12), so:

8(x-5)+12

We multiply parentheses

8x-40+12

We add all the numbers together, and all the variables

8x-28

Back to the equation:

-(8x-28)



We add all the numbers together, and all the variables

2x-(8x-28)+8=0

We get rid of parentheses

2x-8x+28+8=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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