1/3(2x-4)+4=-2/3(x+1)

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Solution for 1/3(2x-4)+4=-2/3(x+1) equation: 



1/3(2x-4)+4=-2/3(x+1)

We move all terms to the left:

1/3(2x-4)+4-(-2/3(x+1))=0



Domain of the equation: 3(2x-4)!=0

x∈R





Domain of the equation: 3(x+1))!=0

x∈R



We calculate fractions


(3xx/(3(2x-4)*3(x+1)))+(-(-6x2)/(3(2x-4)*3(x+1)))+4=0



We calculate terms in parentheses: +(3xx/(3(2x-4)*3(x+1))), so:

3xx/(3(2x-4)*3(x+1))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-(-6x2)/(3(2x-4)*3(x+1))), so:

-(-6x2)/(3(2x-4)*3(x+1))

We add all the numbers together, and all the variables

-(-6x^2)/(3(2x-4)*3(x+1))

We multiply all the terms by the denominator


-(-6x^2)

We get rid of parentheses

6x^2

Back to the equation:

+(6x^2)



determiningTheFunctionDomain
6x^2+3xx+4=0

We move all terms containing x to the left, all other terms to the right

6x^2+3xx=-4

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