-20+2b=2(b-10)

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Solution for -20+2b=2(b-10) equation: 



-20+2b=2(b-10)

We move all terms to the left:

-20+2b-(2(b-10))=0



We calculate terms in parentheses: -(2(b-10)), so:

2(b-10)

We multiply parentheses

2b-20

Back to the equation:

-(2b-20)



We get rid of parentheses

2b-2b+20-20=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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