1/3(24q-12)=8q+4

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Solution for 1/3(24q-12)=8q+4 equation: 



1/3(24q-12)=8q+4

We move all terms to the left:

1/3(24q-12)-(8q+4)=0



Domain of the equation: 3(24q-12)!=0

q∈R



We get rid of parentheses

1/3(24q-12)-8q-4=0

We multiply all the terms by the denominator


-8q*3(24q-12)-4*3(24q-12)+1=0

Wy multiply elements

-24q^2(2-12q(2+1=0

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