7(y-1)-3=-4(-6y+1)-y

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Solution for 7(y-1)-3=-4(-6y+1)-y equation: 



7(y-1)-3=-4(-6y+1)-y

We move all terms to the left:

7(y-1)-3-(-4(-6y+1)-y)=0

We multiply parentheses

7y-(-4(-6y+1)-y)-7-3=0



We calculate terms in parentheses: -(-4(-6y+1)-y), so:

-4(-6y+1)-y

We add all the numbers together, and all the variables

-1y-4(-6y+1)

We multiply parentheses

-1y+24y-4

We add all the numbers together, and all the variables

23y-4

Back to the equation:

-(23y-4)



We add all the numbers together, and all the variables

7y-(23y-4)-10=0

We get rid of parentheses

7y-23y+4-10=0

We add all the numbers together, and all the variables

-16y-6=0

We move all terms containing y to the left, all other terms to the right

-16y=6

y=6/-16

y=-3/8

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