1/3(2-z)=12

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Solution for 1/3(2-z)=12 equation: 



1/3(2-z)=12

We move all terms to the left:

1/3(2-z)-(12)=0



Domain of the equation: 3(2-z)!=0

z∈R



We add all the numbers together, and all the variables

1/3(-1z+2)-12=0

We multiply all the terms by the denominator


-12*3(-1z+2)+1=0

Wy multiply elements

-36z(-+1=0

We use the square of the difference formula

-36z(-1=0

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