20=3(t-3)+4

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Solution for 20=3(t-3)+4 equation: 



20=3(t-3)+4

We move all terms to the left:

20-(3(t-3)+4)=0



We calculate terms in parentheses: -(3(t-3)+4), so:

3(t-3)+4

We multiply parentheses

3t-9+4

We add all the numbers together, and all the variables

3t-5

Back to the equation:

-(3t-5)



We get rid of parentheses

-3t+5+20=0

We add all the numbers together, and all the variables

-3t+25=0

We move all terms containing t to the left, all other terms to the right

-3t=-25

t=-25/-3

t=8+1/3

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