1/3(15n+18)+3n-4=2(4n+2)

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Solution for 1/3(15n+18)+3n-4=2(4n+2) equation: 



1/3(15n+18)+3n-4=2(4n+2)

We move all terms to the left:

1/3(15n+18)+3n-4-(2(4n+2))=0



Domain of the equation: 3(15n+18)!=0

n∈R



We add all the numbers together, and all the variables

3n+1/3(15n+18)-(2(4n+2))-4=0

We multiply all the terms by the denominator


3n*3(15n+18)-((2(4n+2)))*3(15n+18)-4*3(15n+18)+1=0



We calculate terms in parentheses: -((2(4n+2)))*3(15n+18), so:

(2(4n+2)))*3(15n+18



Wy multiply elements

9n^2(1-((2(4n+2)))*3(15n+18)-12n(1+1=0

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