(=12-0.5x)(36+2x)

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Solution for (=12-0.5x)(36+2x) equation: 



(=12-0.5x)(36+2x)

We move all terms to the left:

(-(12-0.5x)(36+2x))=0

We add all the numbers together, and all the variables

(-(-0.5x+12)(2x+36))=0

We multiply parentheses ..

(-(+0x^2+0x+24x+432))=0



We calculate terms in parentheses: +(-(+0x^2+0x+24x+432)), so:

-(+0x^2+0x+24x+432)

We get rid of parentheses

-0x^2-0x-24x-432

We add all the numbers together, and all the variables

-1x^2-25x-432

Back to the equation:

+(-1x^2-25x-432)



We get rid of parentheses

-1x^2-25x-432=0

a = -1; b = -25; c = -432;
Δ = b2-4ac
Δ = -252-4·(-1)·(-432)
Δ = -1103
Delta is less than zero, so there is no solution for the equation

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