1/3(12z-18)=2z-4

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Solution for 1/3(12z-18)=2z-4 equation: 



1/3(12z-18)=2z-4

We move all terms to the left:

1/3(12z-18)-(2z-4)=0



Domain of the equation: 3(12z-18)!=0

z∈R



We get rid of parentheses

1/3(12z-18)-2z+4=0

We multiply all the terms by the denominator


-2z*3(12z-18)+4*3(12z-18)+1=0

Wy multiply elements

-6z^2(1+12z(1+1=0

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