4(2-6n)=128

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Solution for 4(2-6n)=128 equation: 



4(2-6n)=128

We move all terms to the left:

4(2-6n)-(128)=0

We add all the numbers together, and all the variables

4(-6n+2)-128=0

We multiply parentheses

-24n+8-128=0

We add all the numbers together, and all the variables

-24n-120=0

We move all terms containing n to the left, all other terms to the right

-24n=120

n=120/-24

n=-5

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