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1/2z+6=3/2(z-6)
We move all terms to the left:
1/2z+6-(3/2(z-6))=0
Domain of the equation: 2z!=0
z!=0/2
z!=0
z∈R
Domain of the equation: 2(z-6))!=0We calculate fractions
z∈R
(2zz/(4z^2z+(-(3*2z)/(4z^2z+6=0
We can not solve this equation
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