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1/2y+5/6=4/3y-5
We move all terms to the left:
1/2y+5/6-(4/3y-5)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 3y-5)!=0We get rid of parentheses
y∈R
1/2y-4/3y+5+5/6=0
We calculate fractions
90y^2/216y^2+108y/216y^2+(-288y)/216y^2+5=0
We multiply all the terms by the denominator
90y^2+108y+(-288y)+5*216y^2=0
Wy multiply elements
90y^2+1080y^2+108y+(-288y)=0
We get rid of parentheses
90y^2+1080y^2+108y-288y=0
We add all the numbers together, and all the variables
1170y^2-180y=0
a = 1170; b = -180; c = 0;
Δ = b2-4ac
Δ = -1802-4·1170·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-180}{2*1170}=\frac{0}{2340} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+180}{2*1170}=\frac{360}{2340} =2/13 $
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