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1/2y+3/5y+2/3y=1/3
We move all terms to the left:
1/2y+3/5y+2/3y-(1/3)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 3y!=0We add all the numbers together, and all the variables
y!=0/3
y!=0
y∈R
1/2y+3/5y+2/3y-(+1/3)=0
We get rid of parentheses
1/2y+3/5y+2/3y-1/3=0
We calculate fractions
We do not support eypression: y^3
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