2(2z-68)=3z-94

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Solution for 2(2z-68)=3z-94 equation: 



2(2z-68)=3z-94

We move all terms to the left:

2(2z-68)-(3z-94)=0

We multiply parentheses

4z-(3z-94)-136=0

We get rid of parentheses

4z-3z+94-136=0

We add all the numbers together, and all the variables

z-42=0

We move all terms containing z to the left, all other terms to the right

z=42

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