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1/2x=6x
We move all terms to the left:
1/2x-(6x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-6x+1/2x=0
We multiply all the terms by the denominator
-6x*2x+1=0
Wy multiply elements
-12x^2+1=0
a = -12; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-12)·1
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-12}=\frac{0-4\sqrt{3}}{-24} =-\frac{4\sqrt{3}}{-24} =-\frac{\sqrt{3}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-12}=\frac{0+4\sqrt{3}}{-24} =\frac{4\sqrt{3}}{-24} =\frac{\sqrt{3}}{-6} $
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