7(c-4)=3

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Solution for 7(c-4)=3 equation:



7(c-4)=3
We move all terms to the left:
7(c-4)-(3)=0
We multiply parentheses
7c-28-3=0
We add all the numbers together, and all the variables
7c-31=0
We move all terms containing c to the left, all other terms to the right
7c=31
c=31/7
c=4+3/7

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