1/2x-4=1/5x-7

Solution for 1/2x-4=1/5x-7 equation:

1/2x-4=1/5x-7

We move all terms to the left:

1/2x-4-(1/5x-7)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 5x-7)!=0

x∈R


We get rid of parentheses

1/2x-1/5x+7-4=0

We calculate fractions


5x/10x^2+(-2x)/10x^2+7-4=0

We add all the numbers together, and all the variables

5x/10x^2+(-2x)/10x^2+3=0

We multiply all the terms by the denominator


5x+(-2x)+3*10x^2=0

Wy multiply elements

30x^2+5x+(-2x)=0

We get rid of parentheses

30x^2+5x-2x=0

We add all the numbers together, and all the variables

30x^2+3x=0

a = 30; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·30·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*30}=\frac{-6}{60}
=-1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*30}=\frac{0}{60}
=0
$