4(x-1)-2(x+3)=4-5(2x-2)

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Solution for 4(x-1)-2(x+3)=4-5(2x-2) equation: 



4(x-1)-2(x+3)=4-5(2x-2)

We move all terms to the left:

4(x-1)-2(x+3)-(4-5(2x-2))=0

We multiply parentheses

4x-2x-(4-5(2x-2))-4-6=0



We calculate terms in parentheses: -(4-5(2x-2)), so:

4-5(2x-2)

determiningTheFunctionDomain
-5(2x-2)+4

We multiply parentheses

-10x+10+4

We add all the numbers together, and all the variables

-10x+14

Back to the equation:

-(-10x+14)



We add all the numbers together, and all the variables

2x-(-10x+14)-10=0

We get rid of parentheses

2x+10x-14-10=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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