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1/2x-3=4-5/3x
We move all terms to the left:
1/2x-3-(4-5/3x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(-5/3x+4)-3=0
We get rid of parentheses
1/2x+5/3x-4-3=0
We calculate fractions
3x/6x^2+10x/6x^2-4-3=0
We add all the numbers together, and all the variables
3x/6x^2+10x/6x^2-7=0
We multiply all the terms by the denominator
3x+10x-7*6x^2=0
We add all the numbers together, and all the variables
13x-7*6x^2=0
Wy multiply elements
-42x^2+13x=0
a = -42; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-42)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-42}=\frac{-26}{-84} =13/42 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-42}=\frac{0}{-84} =0 $
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