4(2z+5)=5-3(z-5)

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Solution for 4(2z+5)=5-3(z-5) equation: 



4(2z+5)=5-3(z-5)

We move all terms to the left:

4(2z+5)-(5-3(z-5))=0

We multiply parentheses

8z-(5-3(z-5))+20=0



We calculate terms in parentheses: -(5-3(z-5)), so:

5-3(z-5)

determiningTheFunctionDomain
-3(z-5)+5

We multiply parentheses

-3z+15+5

We add all the numbers together, and all the variables

-3z+20

Back to the equation:

-(-3z+20)



We get rid of parentheses

8z+3z-20+20=0

We add all the numbers together, and all the variables

11z=0

z=0/11

z=0

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