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1/2x-3/5x=-3/10
We move all terms to the left:
1/2x-3/5x-(-3/10)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/2x-3/5x+3/10=0
We calculate fractions
150x^2/100x^2+50x/100x^2+(-60x)/100x^2=0
We multiply all the terms by the denominator
150x^2+50x+(-60x)=0
We get rid of parentheses
150x^2+50x-60x=0
We add all the numbers together, and all the variables
150x^2-10x=0
a = 150; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·150·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*150}=\frac{0}{300} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*150}=\frac{20}{300} =1/15 $
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