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(13+2x)(17+2x)=396
We move all terms to the left:
(13+2x)(17+2x)-(396)=0
We add all the numbers together, and all the variables
(2x+13)(2x+17)-396=0
We multiply parentheses ..
(+4x^2+34x+26x+221)-396=0
We get rid of parentheses
4x^2+34x+26x+221-396=0
We add all the numbers together, and all the variables
4x^2+60x-175=0
a = 4; b = 60; c = -175;
Δ = b2-4ac
Δ = 602-4·4·(-175)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-80}{2*4}=\frac{-140}{8} =-17+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+80}{2*4}=\frac{20}{8} =2+1/2 $
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