1/2x-20-x=3(2x-1)-2x-1)

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Solution for 1/2x-20-x=3(2x-1)-2x-1) equation: 



1/2x-20-x=3(2x-1)-2x-1)

We move all terms to the left:

1/2x-20-x-(3(2x-1)-2x-1))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We add all the numbers together, and all the variables

-1x+1/2x-(3(2x-1)-2x-1))-20=0

We multiply all the terms by the denominator


-1x*2x-((3(2x-1)-2x-1))-20)*2x+1=0



We calculate terms in parentheses: -((3(2x-1)-2x-1)), so:

(3(2x-1)-2x-1)



We calculate terms in parentheses: +(3(2x-1)-2x-1), so:

3(2x-1)-2x-1

We add all the numbers together, and all the variables

-2x+3(2x-1)-1

We multiply parentheses

-2x+6x-3-1

We add all the numbers together, and all the variables

4x-4

Back to the equation:

+(4x-4)



We get rid of parentheses

4x-4

Back to the equation:

-(4x-4)



Wy multiply elements

-2x^2-(4x-4)-20)*2x+1=0

We get rid of parentheses

-2x^2-4x-20)*2x+1+4=0

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