n+n+2=3(n+4)-27

Solution for n+n+2=3(n+4)-27 equation:

n+n+2=3(n+4)-27

We move all terms to the left:

n+n+2-(3(n+4)-27)=0

We add all the numbers together, and all the variables

2n-(3(n+4)-27)+2=0


We calculate terms in parentheses: -(3(n+4)-27), so:

3(n+4)-27

We multiply parentheses

3n+12-27

We add all the numbers together, and all the variables

3n-15

Back to the equation:

-(3n-15)


We get rid of parentheses

2n-3n+15+2=0

We add all the numbers together, and all the variables

-1n+17=0

We move all terms containing n to the left, all other terms to the right

-n=-17

n=-17/-1

n=+17