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1/2x-1/3x=-17/4
We move all terms to the left:
1/2x-1/3x-(-17/4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/2x-1/3x+17/4=0
We calculate fractions
306x^2/96x^2+48x/96x^2+(-32x)/96x^2=0
We multiply all the terms by the denominator
306x^2+48x+(-32x)=0
We get rid of parentheses
306x^2+48x-32x=0
We add all the numbers together, and all the variables
306x^2+16x=0
a = 306; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·306·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*306}=\frac{-32}{612} =-8/153 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*306}=\frac{0}{612} =0 $
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