412=x+(4x-3)+(5x)

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Solution for 412=x+(4x-3)+(5x) equation: 



412=x+(4x-3)+(5x)

We move all terms to the left:

412-(x+(4x-3)+(5x))=0



We calculate terms in parentheses: -(x+(4x-3)+5x), so:

x+(4x-3)+5x

We add all the numbers together, and all the variables

6x+(4x-3)

We get rid of parentheses

6x+4x-3

We add all the numbers together, and all the variables

10x-3

Back to the equation:

-(10x-3)



We get rid of parentheses

-10x+3+412=0

We add all the numbers together, and all the variables

-10x+415=0

We move all terms containing x to the left, all other terms to the right

-10x=-415

x=-415/-10

x=41+1/2

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