1/2x+8=x+4

Solution for 1/2x+8=x+4 equation:

1/2x+8=x+4

We move all terms to the left:

1/2x+8-(x+4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-x-4+8=0

We multiply all the terms by the denominator


-x*2x-4*2x+8*2x+1=0

Wy multiply elements

-2x^2-8x+16x+1=0

We add all the numbers together, and all the variables

-2x^2+8x+1=0

a = -2; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·(-2)·1
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6\sqrt{2}}{2*-2}=\frac{-8-6\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6\sqrt{2}}{2*-2}=\frac{-8+6\sqrt{2}}{-4}
$