3(2-c)=-(c+2)

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Solution for 3(2-c)=-(c+2) equation: 



3(2-c)=-(c+2)

We move all terms to the left:

3(2-c)-(-(c+2))=0

We add all the numbers together, and all the variables

3(-1c+2)-(-(c+2))=0

We multiply parentheses

-3c-(-(c+2))+6=0



We calculate terms in parentheses: -(-(c+2)), so:

-(c+2)

We get rid of parentheses

-c-2

We add all the numbers together, and all the variables

-1c-2

Back to the equation:

-(-1c-2)



We get rid of parentheses

-3c+1c+2+6=0

We add all the numbers together, and all the variables

-2c+8=0

We move all terms containing c to the left, all other terms to the right

-2c=-8

c=-8/-2

c=+4

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