1/2x+6=1/3x-12

Solution for 1/2x+6=1/3x-12 equation:

1/2x+6=1/3x-12

We move all terms to the left:

1/2x+6-(1/3x-12)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x-12)!=0

x∈R


We get rid of parentheses

1/2x-1/3x+12+6=0

We calculate fractions


3x/6x^2+(-2x)/6x^2+12+6=0

We add all the numbers together, and all the variables

3x/6x^2+(-2x)/6x^2+18=0

We multiply all the terms by the denominator


3x+(-2x)+18*6x^2=0

Wy multiply elements

108x^2+3x+(-2x)=0

We get rid of parentheses

108x^2+3x-2x=0

We add all the numbers together, and all the variables

108x^2+x=0

a = 108; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·108·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*108}=\frac{-2}{216}
=-1/108
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*108}=\frac{0}{216}
=0
$