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1/2x+5/8x=18
We move all terms to the left:
1/2x+5/8x-(18)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x!=0We calculate fractions
x!=0/8
x!=0
x∈R
8x/16x^2+10x/16x^2-18=0
We multiply all the terms by the denominator
8x+10x-18*16x^2=0
We add all the numbers together, and all the variables
18x-18*16x^2=0
Wy multiply elements
-288x^2+18x=0
a = -288; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-288)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-288}=\frac{-36}{-576} =1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-288}=\frac{0}{-576} =0 $
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