1/2(7x-2)=1/3(5x-3)

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Solution for 1/2(7x-2)=1/3(5x-3) equation: 



1/2(7x-2)=1/3(5x-3)

We move all terms to the left:

1/2(7x-2)-(1/3(5x-3))=0



Domain of the equation: 2(7x-2)!=0

x∈R





Domain of the equation: 3(5x-3))!=0

x∈R



We calculate fractions


(3x5/(2(7x-2)*3(5x-3)))+(-2x7/(2(7x-2)*3(5x-3)))=0



We calculate terms in parentheses: +(3x5/(2(7x-2)*3(5x-3))), so:

3x5/(2(7x-2)*3(5x-3))

We multiply all the terms by the denominator


3x5

We add all the numbers together, and all the variables

3x^5

We do not support expression: x^5

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