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1/2x+3/4x=50
We move all terms to the left:
1/2x+3/4x-(50)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
4x/8x^2+6x/8x^2-50=0
We multiply all the terms by the denominator
4x+6x-50*8x^2=0
We add all the numbers together, and all the variables
10x-50*8x^2=0
Wy multiply elements
-400x^2+10x=0
a = -400; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-400)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-400}=\frac{-20}{-800} =1/40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-400}=\frac{0}{-800} =0 $
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