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(4z+9)(4+z)=0
We add all the numbers together, and all the variables
(4z+9)(z+4)=0
We multiply parentheses ..
(+4z^2+16z+9z+36)=0
We get rid of parentheses
4z^2+16z+9z+36=0
We add all the numbers together, and all the variables
4z^2+25z+36=0
a = 4; b = 25; c = +36;
Δ = b2-4ac
Δ = 252-4·4·36
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-7}{2*4}=\frac{-32}{8} =-4 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+7}{2*4}=\frac{-18}{8} =-2+1/4 $
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